Shane Lowry shares lead as Rory McIlroy makes move at Bay Hill

Shane Lowry is tied for the lead heading into the final round of the Arnold Palmer Invitational at the Bay Hill Club & Lodge in Orlando.

The former Open champion shot two-under for his third round to move to nine-under-par and share the lead with world number one Scottie Scheffler.

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Lowry dropped a shot early in the round, making bogey on the second hole before adding two birdies on the fourth and sixth holes.

Two bogeys would follow on the eighth and ninth as Lowry turned on one-over for his round, but he got things going early on the back nine with back-to-back birdies on the 11th and 12th.

Another dropped shot would follow on the 14th before a strong finish, which included birdies on 16 and 17, and a solid par on the final hole saw Lowry sign for 70.

Lowry will play the final round alongside the world's top player, however, the duo are just one shot clear of fellow major winner Wyndham Clark, while Will Zalatoris, Russell Henley and Hideki Matsuyama share fourth place on seven-under.

Rory McIlroy has played his way into contention, moving from 30th to a share of eighth place thanks to a fine 68, and the four-time major winner will begin his final round just four shots off the lead.

McIlroy actually found himself two-over for his front nine, however, he powered up the leaderboard on the back nine, posting six birdies during a flawless 30 on the way in.

Seamus Power also enjoyed a positive third round, moving up to a share of 25th place thanks to a fine three-under 69.

The Waterford native will begin his final round on one-under-par for the tournament.